Learn how to solve problems step by step online. 1/(1+-1/(1+-1/(1-sec(x)^2))). Wenden Sie die Formel an: a+\frac{b}{c}=\frac{b+ac}{c}, wobei a=1, b=-1, c=1-\sec\left(x\right)^2, a+b/c=1+\frac{-1}{1-\sec\left(x\right)^2} und b/c=\frac{-1}{1-\sec\left(x\right)^2}. Wenden Sie die Formel an: a+\frac{b}{c}=\frac{b+ac}{c}, wobei a=1, b=-1, c=\frac{-\sec\left(x\right)^2}{1-\sec\left(x\right)^2}, a+b/c=1+\frac{-1}{\frac{-\sec\left(x\right)^2}{1-\sec\left(x\right)^2}} und b/c=\frac{-1}{\frac{-\sec\left(x\right)^2}{1-\sec\left(x\right)^2}}. Wenden Sie die Formel an: \frac{a}{\frac{b}{c}}=\frac{ac}{b}, wobei a=1, b=-1+\frac{-\sec\left(x\right)^2}{1-\sec\left(x\right)^2}, c=\frac{-\sec\left(x\right)^2}{1-\sec\left(x\right)^2}, a/b/c=\frac{1}{\frac{-1+\frac{-\sec\left(x\right)^2}{1-\sec\left(x\right)^2}}{\frac{-\sec\left(x\right)^2}{1-\sec\left(x\right)^2}}} und b/c=\frac{-1+\frac{-\sec\left(x\right)^2}{1-\sec\left(x\right)^2}}{\frac{-\sec\left(x\right)^2}{1-\sec\left(x\right)^2}}. Wenden Sie die Formel an: a+\frac{b}{c}=\frac{b+ac}{c}, wobei a=-1, b=-\sec\left(x\right)^2, c=1-\sec\left(x\right)^2, a+b/c=-1+\frac{-\sec\left(x\right)^2}{1-\sec\left(x\right)^2} und b/c=\frac{-\sec\left(x\right)^2}{1-\sec\left(x\right)^2}.

1/(1+-1/(1+-1/(1-sec(x)^2)))