$$x^2-20x+192$$

$$\sqrt{3}x+6=6$$

$$\int\frac{5x^2+20x+6}{\left(x\right)\left(x+1\right)^2}dx$$

$$3\left(2x+8\right)-12=3x+6$$

$$\frac{dy}{dx}=-\frac{2x+1}{y}$$

$$x\frac{dy}{dx}+y+x=0$$

$$\frac{\cos\:\left(4\theta\:\right)+\cos\:\left(2\theta\:\right)}{\sin\:\left(4\theta\:\right)+\sin\:\left(2\theta\:\right)}=\cot\:\left(3\theta\:\right)$$