Wenden Sie die Formel an: $a\frac{x}{b}$$=\frac{a}{b}x$, wobei $a=3$, $b=-1$, $ax/b=3\left(\frac{\frac{\frac{\frac{\frac{-a}{+8}x^2}{+11}a}{+12}a}{+13}x^2}{-1}\right)$, $x=\frac{\frac{\frac{\frac{-a}{+8}x^2}{+11}a}{+12}a}{+13}x^2$ und $x/b=\frac{\frac{\frac{\frac{\frac{-a}{+8}x^2}{+11}a}{+12}a}{+13}x^2}{-1}$