Wenden Sie die Formel an: $\frac{a}{b}\frac{c}{f}$$=\frac{ac}{bf}$, wobei $a=xy-x$, $b=y^2-1$, $c=y+1$, $a/b=\frac{xy-x}{y^2-1}$, $f=x+2$, $c/f=\frac{y+1}{x+2}$ und $a/bc/f=\frac{xy-x}{y^2-1}\frac{y+1}{x+2}\frac{2x+4}{5x}$

Wenden Sie die Formel an: $\frac{a}{b}\frac{c}{f}$$=\frac{ac}{bf}$, wobei $a=\left(xy-x\right)\left(y+1\right)$, $b=\left(y^2-1\right)\left(x+2\right)$, $c=2x+4$, $a/b=\frac{\left(xy-x\right)\left(y+1\right)}{\left(y^2-1\right)\left(x+2\right)}$, $f=5x$, $c/f=\frac{2x+4}{5x}$ und $a/bc/f=\frac{\left(xy-x\right)\left(y+1\right)}{\left(y^2-1\right)\left(x+2\right)}\frac{2x+4}{5x}$