Learn how to solve problems step by step online. d/dx(((x^2-x)/(x^2+1))^(1/2)). Wenden Sie die Formel an: \frac{d}{dx}\left(x^a\right)=ax^{\left(a-1\right)}\frac{d}{dx}\left(x\right), wobei a=\frac{1}{2} und x=\frac{x^2-x}{x^2+1}. Wenden Sie die Formel an: \left(\frac{a}{b}\right)^n=\left(\frac{b}{a}\right)^{\left|n\right|}, wobei a=x^2-x, b=x^2+1 und n=-\frac{1}{2}. Wenden Sie die Formel an: \frac{d}{dx}\left(\frac{a}{b}\right)=\frac{\frac{d}{dx}\left(a\right)b-a\frac{d}{dx}\left(b\right)}{b^2}, wobei a=x^2-x und b=x^2+1. Wenden Sie die Formel an: \frac{a}{b}\frac{c}{f}=\frac{ac}{bf}, wobei a=1, b=2, c=\frac{d}{dx}\left(x^2-x\right)\left(x^2+1\right)-\left(x^2-x\right)\frac{d}{dx}\left(x^2+1\right), a/b=\frac{1}{2}, f=\left(x^2+1\right)^2, c/f=\frac{\frac{d}{dx}\left(x^2-x\right)\left(x^2+1\right)-\left(x^2-x\right)\frac{d}{dx}\left(x^2+1\right)}{\left(x^2+1\right)^2} und a/bc/f=\frac{1}{2}\sqrt{\frac{x^2+1}{x^2-x}}\frac{\frac{d}{dx}\left(x^2-x\right)\left(x^2+1\right)-\left(x^2-x\right)\frac{d}{dx}\left(x^2+1\right)}{\left(x^2+1\right)^2}.

d/dx(((x^2-x)/(x^2+1))^(1/2))