Learn how to solve problems step by step online. Find the derivative d/dx((3x^2-2xy+-5)/(x^2-4y)). Wenden Sie die Formel an: \frac{d}{dx}\left(x\right)=y=x, wobei d/dx=\frac{d}{dx}, d/dx?x=\frac{d}{dx}\left(\frac{3x^2-2xy-5}{x^2-4y}\right) und x=\frac{3x^2-2xy-5}{x^2-4y}. Wenden Sie die Formel an: y=x\to \ln\left(y\right)=\ln\left(x\right), wobei x=\frac{3x^2-2xy-5}{x^2-4y}. Wenden Sie die Formel an: y=x\to y=x, wobei x=\ln\left(\frac{3x^2-2xy-5}{x^2-4y}\right) und y=\ln\left(y\right). Wenden Sie die Formel an: \ln\left(y\right)=x\to \frac{d}{dx}\left(\ln\left(y\right)\right)=\frac{d}{dx}\left(x\right), wobei x=\ln\left(3x^2-2xy-5\right)-\ln\left(x^2-4y\right).

Find the derivative d/dx((3x^2-2xy+-5)/(x^2-4y))