Übung
$\frac{8x^3+6x^2-3x+1}{2x^2-x+2}$
Schritt-für-Schritt-Lösung
1
Teilen Sie $8x^3+6x^2-3x+1$ durch $2x^2-x+2$
$\begin{array}{l}\phantom{\phantom{;}2x^{2}-x\phantom{;}+2;}{\phantom{;}4x\phantom{;}+5\phantom{;}\phantom{;}}\\\phantom{;}2x^{2}-x\phantom{;}+2\overline{\smash{)}\phantom{;}8x^{3}+6x^{2}-3x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x^{2}-x\phantom{;}+2;}\underline{-8x^{3}+4x^{2}-8x\phantom{;}\phantom{-;x^n}}\\\phantom{-8x^{3}+4x^{2}-8x\phantom{;};}\phantom{;}10x^{2}-11x\phantom{;}+1\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x^{2}-x\phantom{;}+2-;x^n;}\underline{-10x^{2}+5x\phantom{;}-10\phantom{;}\phantom{;}}\\\phantom{;-10x^{2}+5x\phantom{;}-10\phantom{;}\phantom{;}-;x^n;}-6x\phantom{;}-9\phantom{;}\phantom{;}\\\end{array}$
$4x+5+\frac{-6x-9}{2x^2-x+2}$
Endgültige Antwort auf das Problem
$4x+5+\frac{-6x-9}{2x^2-x+2}$