Übung
$\frac{7x-2x^3-5}{x+2}$
Schritt-für-Schritt-Lösung
1
Teilen Sie $7x-2x^3-5$ durch $x+2$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+2;}{-2x^{2}+4x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+2\overline{\smash{)}-2x^{3}\phantom{-;x^n}+7x\phantom{;}-5\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+2;}\underline{\phantom{;}2x^{3}+4x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{\phantom{;}2x^{3}+4x^{2};}\phantom{;}4x^{2}+7x\phantom{;}-5\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+2-;x^n;}\underline{-4x^{2}-8x\phantom{;}\phantom{-;x^n}}\\\phantom{;-4x^{2}-8x\phantom{;}-;x^n;}-x\phantom{;}-5\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+2-;x^n-;x^n;}\underline{\phantom{;}x\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}x\phantom{;}+2\phantom{;}\phantom{;}-;x^n-;x^n;}-3\phantom{;}\phantom{;}\\\end{array}$
$-2x^{2}+4x-1+\frac{-3}{x+2}$
Endgültige Antwort auf das Problem
$-2x^{2}+4x-1+\frac{-3}{x+2}$