$\int\:\frac{1}{\left(x-1\right)\left(x+1\right)}dx$

$f\:\left(x\right)=\frac{1}{16}x^2+1s$

$\left(x^4-3\right)\left(x^4+7\right)$

$-\left(x^2+28\right)\cdot\left(2x+4\right)$

$309.2096+573.3856$

$\sin\:\left(x\right)\cos\:\left(x\right)+\sin\:\left(x\right)\cos\:\left(3x\right)=1$

$\left(6a^2b^3-11\right)^2$