Learn how to solve polynomielle faktorisierung problems step by step online. cos(0.369pi)^2+sin(x)^2=1. Wenden Sie die Formel an: x+a=b\to x=b-a, wobei a=\cos\left(0.369\pi \right)^2, b=1, x+a=b=\cos\left(0.369\pi \right)^2+\sin\left(x\right)^2=1, x=\sin\left(x\right)^2 und x+a=\cos\left(0.369\pi \right)^2+\sin\left(x\right)^2. Anwendung der trigonometrischen Identität: 1-\cos\left(\theta \right)^2=\sin\left(\theta \right)^2, wobei x=0.369\pi . Wenden Sie die Formel an: x^a=b\to \left(x^a\right)^{\frac{1}{a}}=\pm b^{\frac{1}{a}}, wobei a=2, b=\sin\left(0.369\pi \right)^2 und x=\sin\left(x\right). Simplify \left(\sin\left(x\right)^2\right)^{0.5} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals 0.5.

cos(0.369pi)^2+sin(x)^2=1